3.3.71 \(\int \frac {x^m}{1+2 x^4+x^8} \, dx\) [271]

Optimal. Leaf size=32 \[ \frac {x^{1+m} \, _2F_1\left (2,\frac {1+m}{4};\frac {5+m}{4};-x^4\right )}{1+m} \]

[Out]

x^(1+m)*hypergeom([2, 1/4+1/4*m],[5/4+1/4*m],-x^4)/(1+m)

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Rubi [A]
time = 0.01, antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {28, 371} \begin {gather*} \frac {x^{m+1} \, _2F_1\left (2,\frac {m+1}{4};\frac {m+5}{4};-x^4\right )}{m+1} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^m/(1 + 2*x^4 + x^8),x]

[Out]

(x^(1 + m)*Hypergeometric2F1[2, (1 + m)/4, (5 + m)/4, -x^4])/(1 + m)

Rule 28

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/c^p, Int[u*(b/2 + c*x^n)^(2*
p), x], x] /; FreeQ[{a, b, c, n}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {x^m}{1+2 x^4+x^8} \, dx &=\int \frac {x^m}{\left (1+x^4\right )^2} \, dx\\ &=\frac {x^{1+m} \, _2F_1\left (2,\frac {1+m}{4};\frac {5+m}{4};-x^4\right )}{1+m}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 34, normalized size = 1.06 \begin {gather*} \frac {x^{1+m} \, _2F_1\left (2,\frac {1+m}{4};1+\frac {1+m}{4};-x^4\right )}{1+m} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^m/(1 + 2*x^4 + x^8),x]

[Out]

(x^(1 + m)*Hypergeometric2F1[2, (1 + m)/4, 1 + (1 + m)/4, -x^4])/(1 + m)

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {x^{m}}{x^{8}+2 x^{4}+1}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m/(x^8+2*x^4+1),x)

[Out]

int(x^m/(x^8+2*x^4+1),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(x^8+2*x^4+1),x, algorithm="maxima")

[Out]

integrate(x^m/(x^8 + 2*x^4 + 1), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(x^8+2*x^4+1),x, algorithm="fricas")

[Out]

integral(x^m/(x^8 + 2*x^4 + 1), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{m}}{\left (x^{4} + 1\right )^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m/(x**8+2*x**4+1),x)

[Out]

Integral(x**m/(x**4 + 1)**2, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(x^8+2*x^4+1),x, algorithm="giac")

[Out]

integrate(x^m/(x^8 + 2*x^4 + 1), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {x^m}{x^8+2\,x^4+1} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m/(2*x^4 + x^8 + 1),x)

[Out]

int(x^m/(2*x^4 + x^8 + 1), x)

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